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the velocity of a falling object can be found using the formula v^3=64h, where v is the velocity (in ft per second) and h is the distance the object has already fallen. What is the velocity of the object after a 10-ft fall? How much does the velocity increase if the objects falls 20 ft rather than 10?
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v^3? you sure that isnt v^2?
yeah your right, its v^2
im a mind reader lol
it was either that or we were moving into the fourth dimension ;)
v = 8sqrt(h) at 10 ft, v = 8sqrt(10) at 20 ft, v = 8sqrt(20) = 16sqrt(5)
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lol. thanks.
:) youre welcome; not sure if I anwered the second part ....but thats the best I got ;)
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