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Mathematics 11 Online
OpenStudy (anonymous):

Find the of x for which the geometric series converges. [(x-1)/2]^n-1

OpenStudy (anonymous):

Find the * value* of x..

OpenStudy (anonymous):

Do you think you could help chaguanas?

OpenStudy (anonymous):

Let's see, checking my book

OpenStudy (anonymous):

What you do is write a few values of the series, giving n value 1, then 2, then 3. After a few you would know what the sum looks like. Then you can find x

OpenStudy (anonymous):

I'm not sure what the series would even be written out as... :/

OpenStudy (anonymous):

Oh, I'm sorry. Your note confused me when you said find value of x.

OpenStudy (anonymous):

Oh, i left that part out of the original question, so I was just throwing that in that there...

OpenStudy (anonymous):

So how should i go about this?

OpenStudy (anonymous):

Ratio test

OpenStudy (anonymous):

I would say x=1. Ratio test, take limit leaves x-1. Not confident on my answer. May be Xavier can check me.

OpenStudy (anonymous):

ok. Thanks!

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