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Find the of x for which the geometric series converges. [(x-1)/2]^n-1
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Find the * value* of x..
Do you think you could help chaguanas?
Let's see, checking my book
What you do is write a few values of the series, giving n value 1, then 2, then 3. After a few you would know what the sum looks like. Then you can find x
I'm not sure what the series would even be written out as... :/
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Oh, I'm sorry. Your note confused me when you said find value of x.
Oh, i left that part out of the original question, so I was just throwing that in that there...
So how should i go about this?
Ratio test
I would say x=1. Ratio test, take limit leaves x-1. Not confident on my answer. May be Xavier can check me.
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ok. Thanks!
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