Question

Solve for x: square route of 3x^2-8 (end square route) + x=0

Answer 1

To solve when there is a square root involved. you need to get the square root by itself on one side of the equation...

So you would subtract x

Answer 2

sqrt(3x^2 - 8) = -x

Answer 3

Then you square both sides.

Answer 4

sqrt(3x^2 - 8)^2 = (-x)^2

squaring a square root cancels each other out leaving you with what is left under the square root sign

3x^2 - 8 = x^2

Answer 5

Make the equation = to 0

2x^2 - 8 = 0

Answer 6

Factor

2(x^2 - 4) = 0
2(x + 2)(x - 2) = 0

x = -2 or x = 2

Answer 7

Thanks!