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Algebra 2 Help please. ((x+1)^4 -1)
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Simplify...
This is the difference of two squares ((x + 1)^2 + 1))((x + 1)^2 - 1) the second one factors down further ((x + 1)^2 + 1)((x + 1) + 1)((x + 1) - 1)
((x + 1)^2 + 1) = (x + 1)(x + 1) + 1 x^2 + 2x + 1 + 1 (x^2 + 2x + 2)
The other two are ((x + 1) + 1) = (x + 2) ((x + 1) - 1) = x
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So x(x + 2)(x^2 + 2x + 2)
I got x^4+4x^3+6x^2+4x...but i dont knoww..
I think it needs to be factored as I did above.
I dont understand how you did it.
These ones are harder to spot but it is basically a^2 - b^2. (x+1)^4 is basically the square of (x+1)^2 and 1 you know can be squared to equal 1
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