Mathematics
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OpenStudy (anonymous):
Differentiate the given funtion:
f(x)= ln (x+1)/(x-1)
I get -2/(x-1)^2
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OpenStudy (anonymous):
amistre
OpenStudy (anonymous):
wait is it ln(x+1/x-1)?
OpenStudy (anonymous):
who wats to share google doc
OpenStudy (anonymous):
who has g mail
OpenStudy (amistre64):
ln[(x+1)/(x-1)] = ln(x+1) - ln(x+1)
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OpenStudy (amistre64):
hi mary :)
OpenStudy (anonymous):
amistre answer me
OpenStudy (amistre64):
1/(x+1) - 1/(x-1) is good for the derivative
OpenStudy (anonymous):
do you have google account
OpenStudy (amistre64):
lotsa people have gmail...
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OpenStudy (anonymous):
wht to share on goole doc
OpenStudy (amistre64):
no thanx mary :)
OpenStudy (anonymous):
i need help there
OpenStudy (anonymous):
whats yuor gmail
OpenStudy (amistre64):
tony031172@gmail is my spam catcher
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OpenStudy (anonymous):
lol
OpenStudy (amistre64):
(x-1) - (x+1) -2
----------- = ------ is what I get
(x-1)(x+1) x^2-1
OpenStudy (anonymous):
\[\frac{1}{(-1+x) (1+x)}-\frac{\text{Log}[1+x]}{(-1+x)^2} \]
\[\int\limits \left(\frac{1}{(-1+x) (1+x)}-\frac{\text{Log}[1+x]}{(-1+x)^2}\right) \, dx=\frac{\text{Log}[1+x]}{-1+x} \]
OpenStudy (anonymous):
amistre plz check your gmail
OpenStudy (anonymous):
sorry i started a new one. too much going on here
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OpenStudy (amistre64):
lincoln assassination....
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
differentiate is derivatives or integrals?
OpenStudy (anonymous):
amistrre join
OpenStudy (anonymous):
plz
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OpenStudy (amistre64):
mary: im good with math; not english lit projects :)
OpenStudy (anonymous):
idc just go to google doc
OpenStudy (anonymous):
John Boothe was the culprit
OpenStudy (anonymous):
Very sorry about the mutiple postings. This whole business is not working out for me.
OpenStudy (amistre64):
Boothe was framed!! lol
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OpenStudy (anonymous):
ok chague do you have gamail
OpenStudy (anonymous):
join my google doc
OpenStudy (anonymous):
vp andrew jackson wanted 187 Lincoln, so he could get all the cheese, Boothe obliged