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Mathematics 19 Online
OpenStudy (anonymous):

Graph the ellipse (9x^2)+(16y^2)-36x+32y-92=0

OpenStudy (anonymous):

OpenStudy (anonymous):

next time just use http://www.wolframalpha.com/, and type your equation of whatever there.

OpenStudy (anonymous):

9x2-36x +16y2+32y=92 9(x2-4x)+16(y2+2y)=92 9(x2-4x+4-4)+16(y2+2y+1-1)=92

OpenStudy (anonymous):

i did, but it doesn't tell me the points so it doesn't help much

OpenStudy (anonymous):

9(x-2)^2 -36 +16(y+1)^2 -16=92

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=%289x^2%29%2B%2816y^2%29-36x%2B32y-92%3D0 Click on properties on geormetric figure...

OpenStudy (anonymous):

9(x-2)^2 +16(y+1)^2= 144

OpenStudy (anonymous):

9/144(x-2)^2 +16/144(y+1)^2= 1

OpenStudy (anonymous):

(x-2)^2/144/9 + (y+1)^2 / 144/16=1

OpenStudy (anonymous):

(x-2)^2/16 + (y+1)^2 / 9=1

OpenStudy (anonymous):

(x-2)^2/4^2 + (y+1)^2 /3^2=1

OpenStudy (anonymous):

wtf are you doing lol?

OpenStudy (anonymous):

(x-2)^2/4^2 + [y-(-1)]^2 /3^2=1

OpenStudy (anonymous):

tryceo you can't take wolfram in test. You need to do it manually.

OpenStudy (anonymous):

If you wanted to graph it by hand.. then just complete the squares and then you are fine.

OpenStudy (anonymous):

I dont remember the process for completing squares

OpenStudy (anonymous):

http://www.youtube.com/watch?v=gzm-uhj06q8 Watch this...

OpenStudy (anonymous):

what shorthand you use for quotient rule f(x) or what?

OpenStudy (anonymous):

Sorry, ignore above. I was working with someone else.

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