hey can anybody solve this question .... if f(x)=x2-x,show that f(x+1)=f(-x)

Question

anonymous · Answer

f(x+1) = (x+1)^2 - (x+1)
= x^2 +2x +1 - x -1
=x^2 +x
= f(-x)

anonymous · Answer

f(x+1)=(x+1)^2 -(x+1)
         = (x+1)((x+1-1)
        = x(x-1)=f(x)...ur statement is wrong..maybe??

anonymous · Answer

hey thanx mate

anonymous · Answer

but iam still blank :S

anonymous · Answer

nah ive checked it statement is right

anonymous · Answer

ankur $$f(x)\neq x(x-1)$$

anonymous · Answer

err nvm, durr

radar · Answer

$$f(x)=x ^{2}-x$$ This was given
Show that f(x+1) = f(-x).  Work out each one and see if it is true
First do f(x+1)$$f(x+1)=(x+1)^{2}-(x+1)=x ^{2}+2x+1-x-1=x ^{2}+x$$
Now work it out for -x
$$f(-x)=(-x)^{2}-(-x)=x ^{2}+x$$
The results look the same to me