Question

hey can anybody solve this question .... if f(x)=x2-x,show that f(x+1)=f(-x)

Answer 1

f(x+1) = (x+1)^2 - (x+1)
= x^2 +2x +1 - x -1
=x^2 +x
= f(-x)

Answer 2

f(x+1)=(x+1)^2 -(x+1)
= (x+1)((x+1-1)
= x(x-1)=f(x)...ur statement is wrong..maybe??

Answer 3

hey thanx mate

Answer 4

but iam still blank :S

Answer 5

nah ive checked it statement is right

Answer 6

ankur \[f(x)\neq x(x-1)\]

Answer 7

err nvm, durr

Answer 8

\[f(x)=x ^{2}-x\] This was given
Show that f(x+1) = f(-x). Work out each one and see if it is true
First do f(x+1)\[f(x+1)=(x+1)^{2}-(x+1)=x ^{2}+2x+1-x-1=x ^{2}+x\]
Now work it out for -x
\[f(-x)=(-x)^{2}-(-x)=x ^{2}+x\]
The results look the same to me