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Can someone solve xsquared+4x+5 please?
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(x+5)(x-1) which would then equal. -5 and 1
\[x^{2}+4x+5\]
Complete the square (x+2)^2 + 1
\[x=-b \pm \sqrt{b^2-4(a timesc)}\] a would be the x^2 b would be the value with x and c is the one without the value
.......it would be easier for them to foil.....
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this is so easy
and all of that would be divided by 2a
you don't foil that.. x squared+4x+5 you find the gcf that goes into 4x which then would add up to 4 and when you multiply you would get 5 and the answer is (x-1) (x-5) the (x) part is coming from the x2... i have it written out if you want a picture of it..
....how does -1 and -5 equal positive 4??
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