how to solve equation ie A^4+7a^2+1(3)

Question

anonymous · Answer

is it supposed to be A and a? and that last part is just 1 * 3?

anonymous · Answer

$$a ^{4}+7a ^{2}+3$$ is that the equation?

anonymous · Answer

yea

anonymous · Answer

use quad formula
a= (-i) sqrt[(7 - Sqrt[37])/2],  i Sqrt[(7 - Sqrt[37])/2], (-i) Sqrt[(7 + Sqrt[37])/2], i Sqrt[(7 + Sqrt[37])/2]

anonymous · Answer

it is a parabola with a vertex at (0,3) and never crosses the x-axis so no solutions (roots, zeroes)

anonymous · Answer

are you sure that this equation
 has no solution

anonymous · Answer

btm is right, there are no REAL solutions
notice how all the values i provided has i in it? it's imaginery

anonymous · Answer

are you graphing to find a solution...what section/concept is it

anonymous · Answer

actually im a student of accoutant .today was our test and in that test this was the question .to solve this equation

anonymous · Answer

can u please tell me the reason why it is unsolveable

anonymous · Answer

it is unsolvable by graphing because it will not touch the x axis
but mathematically (ie using the quadratic formula)
you will be able to get the roots
they are the real roots, they're imaginary roots

anonymous · Answer

thanks buddy

anonymous · Answer

sure thing