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find the antiderivatives? 3x^3-x(square root)x+2 dx=???
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change \[\sqrt{x}\] to \[x^{(1 \2 )}\] then combine x and \[x ^{(1 \ 2)}\]
K, so it would leave me with 3x^3-??? I'm drawing a blank...
College algebra: when multiplying, add exponents
x^3/2?
good job.
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I dont understand how to break down 3x^3 to find the antiderivatve of that
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