can someone please tell me how to solve this differential equation. y^6 + y = 0 . :(

Question

dumbcow · Answer

where is dy/dx

anonymous · Answer

dy/dx has not been given .this is a question related to higher order linear equations.

anonymous · Answer

i am unable to figure out how to find the roots , please help if you can

dumbcow · Answer

im not sure
if you solve this for y
y(y^5+1)=0
y=0
y=-1

anonymous · Answer

anonymous · Answer

its something of this sort :S But i'm unable to figure out how to solve it for degree 6

dumbcow · Answer

oh ok thats not y^6 thats really dy/dx ^6
sorry i only took up to first order DE

dumbcow · Answer

look at example 5 on the link you gave me, that seems to match your problem
you would have
r^6 = -1
r = (-1)^1/6

anonymous · Answer

ohh ok i kinda get it..In place of pie-by-4 and pie-by-2 , there will be pie-by-3 and pie-by-6. Am i right ?

dumbcow · Answer

i think so but not positive
sorry

anonymous · Answer

oh its ok thanks :)