Question

help with this equation PLEASE!?

Answer 1

\[y ^{5}-81y=0\]

Answer 2

First factor out a y

Answer 3

I know there are 5 solutions, i'm just not sure exactly what the next steps look like.

Answer 4

leaving
y=0
y^4 - 81 =0

Answer 5

y^4=81
y = +-81^1/4

Answer 6

oh ok, so the other ones would be the same thing but 1/3, 1/3, 1...?

Answer 7

i meant 1/2

Answer 8

hmm fourth root of 81 is 3
3*3*3*3=81
solutions would be 0,3,-3

Answer 9

it says it has 5 solutions

Answer 10

the other 2 would be non-real solutions i believe

Answer 11

if you graph this you will see it only crosses x-axis 3 times

Answer 12

I don't need to graph it I just need to type in the 5 answers. What would the non real solutions be?

Answer 13

ok
y^2 +9 =0
y^2 = -9
y = sqrt(-9) = sqrt(9)*i
y = +-3i

Answer 14

so 0,-9,\[\sqrt{9}\sqrt{9}\]i, and -3i?

Answer 15

sorry but my online assignment is picky with the format so i want to make sure I type it in correct

Answer 16

oops, just realized i typed it wrong

Answer 17

you are correct
y = 0,-3,3,-3i,3i

Answer 18

Oh, because it's the square root of that so this is the final answer.. Gotca, thanks!