Question

find the four odd consecutive integers whose sum is 132.and find the product of the smallest and largest integer?

Answer 1

Let x be the first one of the 4. That means that the second one is?

Answer 2

x+1

Answer 3

right?

Answer 4

Not quite. x+1 would be the next integer, but not the next odd one. Each odd integer is how far away from the next odd integer?

Answer 5

could you please explain me this in detail?

Answer 6

Lets say that 3 is the first odd integer, What is the next odd integer after 3?

Answer 7

5

Answer 8

And 3 is how far from 5

Answer 9

1

Answer 10

5-3 = 1?

Answer 11

right

Answer 12

I'm pretty sure 5-3 = 2

Answer 13

right

Answer 14

So how far away from 5 is the next odd integer?

Answer 15

3

Answer 16

sorry 2

Answer 17

Right

Answer 18

So if x is the first odd integer in our series, then what are the other 4?

Answer 19

Err other 3 rather

Answer 20

X+3,X+5,X+7

Answer 21

what happen is this right?

Answer 22

Not quite. The distance between each one is 2.
So the first one is x, the second is x+2, the third is x+4, and the fourth?

Answer 23

x+6

Answer 24

is this right?

Answer 25

please give a reply

Answer 26

Yes. Ok, so now we have the sum of these is 132.

Answer 27

ok cant we do this like firs intger as x and other integrs like x+1,x+2,x+3,x+4

Answer 28

No, because if x is 3, the x+1 would be 4 which is not the next odd integer.

Answer 29

We need them all to be odd, so we need to add 2 every time, not 1

Answer 30

ok thankyou

Answer 31

it helped me

Answer 32

Ok so now you have the equation

x + x+2 + x+4 + x+6 = 132. Solve for x.