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ln8x=4 ?
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Yes
\[ln(8x) = 4 \iff e^4 = 8x\]
By the definition of the logarithm
So then what would you do?
how do i solve for x?
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Well, you have \(8x = e^4\) If I told you that 7a = 25, how would you solve for a?
divide 25 by 7
would the answer be 6.82?
Yep, or at least that's a close approximation.
okay, so if were to have ln(5-x)=12 how would ibegin with solving that?
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Same deal. \[ln(a) = b \iff e^b = a\]
Those two expressions are equivalent.
ok, so e to the 12 power = 5-x ?
Yes
does it equal approx -162749.8?
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yep
thank you
Very welcome =)
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