Question

6ab^2/5a^3b divided by 12ab/15a^5b
I dont know if im supposed to flip the second half and make the division into a multiplication or simplify first.

Answer 1

Alright, first let's cut down the question into 2 parts :):\[\frac{6ab^2}{5a^3b}\]

this part is divide by :

\[\frac{12ab}{15a^5b}\]

now let's just write it down in a simpler form ^_^:

\[\frac{6ab^2}{5a^3b} \div \frac{12ab}{15a^5b}\]

now there's a rule that says, when you divide 2 fractions or any other number, you have to flip the other fraction/number and multiply instead of divide like this:
\[\frac{6ab^2}{5a^3b} \times \frac{15a^5b}{12ab}\]

now let's simplify :)

\[= \frac{3a^2b}{2}\]

is it clearer now :)?

Answer 2

thanks, so does that mean the flipping rule always comes first no matter what?

Answer 3

yep ^_^ and np