Question

. Write the complex binomial expansion. (5x+3)^4

Answer 1

you have to know combinations like
4 choose1, 4 choose2

Answer 2

14641 might work?

Answer 3

i am so lost in this one....

Answer 4

(5x)^4+4(5x)^3 (3)+6(5x)^2(3)^2+4(5x)(3)^3+(3)^4 if i see it right; but what do you refer to as complex?

Answer 5

with imaginary numbers? or simply complicated?

Answer 6

4C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4)

Answer 7

and im finished on here, going to go to sleep

Answer 8

i dont know, thats what my problem says, exactly how i wrote it

Answer 9

^ "with imaginary numbers"?

thats not even possible.

They wanted the binomail expansion , they want the binomial coefficents, not just pascals triangle

Answer 10

then elecs answer looks to be close to what they want :)

Answer 11

so that long thing is the answer ? lol

Answer 12

thats what they mean by "complex"

Answer 13

4C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4)
This is the answer lol wow

Answer 14

I had parts of it right lol ;)

Answer 15

you need to multiply it out it will simplify a little bit

Answer 16

im still in shock that thats the long answer lol

Answer 17

yeah the bigger the exponent, the longer the answer

Answer 18

where do we get the 4c1 and stuff from? the exponent?

Answer 19

yes

Answer 20

:) dint know if that was a fluke, or not :)

Answer 21

no yours above was correct
4C1=4
4C2=6

Answer 22

so elecengineer answer was correst right?

Answer 23

....i wanna say yes, but I dont have a combinatorics button on the calulator ... :/

Answer 24

hmmm.... ok

Answer 25

according to an online nCr calculator, mines good lol :)

Answer 26

but you prolly want the 4C0, 4C1 stuff

Answer 27

4C0 = 1
4C1=4
4C2=6
4C3 = 4
4C4=1
they just represent numbers

Answer 28

nCr = n!/(n-r)!r!

Answer 29

wow this is way over my head