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Mathematics 16 Online
OpenStudy (anonymous):

. Write the complex binomial expansion. (5x+3)^4

OpenStudy (dumbcow):

you have to know combinations like 4 choose1, 4 choose2

OpenStudy (amistre64):

14641 might work?

OpenStudy (anonymous):

i am so lost in this one....

OpenStudy (amistre64):

(5x)^4+4(5x)^3 (3)+6(5x)^2(3)^2+4(5x)(3)^3+(3)^4 if i see it right; but what do you refer to as complex?

OpenStudy (amistre64):

with imaginary numbers? or simply complicated?

OpenStudy (anonymous):

4C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4)

OpenStudy (anonymous):

and im finished on here, going to go to sleep

OpenStudy (anonymous):

i dont know, thats what my problem says, exactly how i wrote it

OpenStudy (anonymous):

^ "with imaginary numbers"? thats not even possible. They wanted the binomail expansion , they want the binomial coefficents, not just pascals triangle

OpenStudy (amistre64):

then elecs answer looks to be close to what they want :)

OpenStudy (anonymous):

so that long thing is the answer ? lol

OpenStudy (anonymous):

thats what they mean by "complex"

OpenStudy (anonymous):

4C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4) This is the answer lol wow

OpenStudy (amistre64):

I had parts of it right lol ;)

OpenStudy (dumbcow):

you need to multiply it out it will simplify a little bit

OpenStudy (anonymous):

im still in shock that thats the long answer lol

OpenStudy (dumbcow):

yeah the bigger the exponent, the longer the answer

OpenStudy (amistre64):

where do we get the 4c1 and stuff from? the exponent?

OpenStudy (dumbcow):

yes

OpenStudy (amistre64):

:) dint know if that was a fluke, or not :)

OpenStudy (dumbcow):

no yours above was correct 4C1=4 4C2=6

OpenStudy (anonymous):

so elecengineer answer was correst right?

OpenStudy (amistre64):

....i wanna say yes, but I dont have a combinatorics button on the calulator ... :/

OpenStudy (anonymous):

hmmm.... ok

OpenStudy (amistre64):

according to an online nCr calculator, mines good lol :)

OpenStudy (amistre64):

but you prolly want the 4C0, 4C1 stuff

OpenStudy (dumbcow):

4C0 = 1 4C1=4 4C2=6 4C3 = 4 4C4=1 they just represent numbers

OpenStudy (dumbcow):

nCr = n!/(n-r)!r!

OpenStudy (anonymous):

wow this is way over my head

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