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lne^-2y im working with Base e and Logarithms, i need step by step help and help understanding please.
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= -2y just from the definition
or if you want a better way of explaining you can bring the power down in front ( its a log law )
\[\log_{a} (x^n) = n \log_{a} (x)\]
so we get (-2y) ln(e) and ln(e) is just 1 , 1( -2y ) =-2y
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