Question

Find the equation of the line tangent to the curve y=e^x *sqrt(3+e^(2x))

Answer 1

First find the derivative.

Answer 2

i believe its:
y'= (e^x)(sqrt(3+e^(2x))+ e^(3x)/(sqrt(3+e^(2x))

Answer 3

oh, it is at the point (0,2)

Answer 4

Well once you find the derivative, the equation of a line is y=mx+b where m is now represented by your derivative function. So it's pretty much a plug and solve problem once you have the derivative.

Answer 5

I believe your derivative is correct also.