Question

can some give me the steps to solve this problem
7e^4x+1=28

Answer 1

First you want to subtract the 1 over and then divide by 7. So you will have e^4x=27/7

Then to get rid of the e, you natural log both sides. So you get 4x=ln(27/7)

Then finally, x=(ln(27/7))/4

Answer 2

okay, I was dividing both sides by 7 first

Answer 3

That would work, you'd just have to make sure that you also divide that 1 by 7. It's usually just simpler to combine constants first.