Question

Solve for x.
log(7)*x+log(7)*(x-1)=log(7)*2x

Answer 1

you'll get this :\[\log_{7}x(x-1) = \log_{7} 2x \]

but I'm not sure whether you're supposed to take the ln of both sides to get rid of the log

Answer 2

when we have (+) and same log bases, then it means multiplication, and when we have (-) and same log bases then we divide ^_^

Answer 3

but if you do take the ln of both sides then you'll get :\[x^2-x=2x \rightarrow x^2-3x=0\]\[x(x-3) = 0\]



so x = 0, 3 ^_^ but I'm not sure though

Answer 4

wow i was totally over thinking it lol
thank you sooo much

Answer 5

np ^_^, but again not sure with the ln part :)