Hi do anyone know how to do Rational Expressions. m+6/m^2-3m+2m-1/m^2+5m-14
is it :\[\frac{m+6}{m^2-3m} + \frac{2m-1}{m^2+5m-14}?\]
m+6m2−3m+2 +2m−1m2+5m−14 there's two (2)s but that setup is right
no fractions? lol I'm confused now
lol yes fractions i just dont know how to put it on. its my first time on this. your set up is right. but you were missing a number 2 on m^2-3m+2 =)
try to put brackets for those with fractions :)
oh, so my equation was right? all I have to do is add a 2?
yes
okay :)
=) your soo awesome for helping me double =D
lol ^_^
thank you )
lol
alright, so after factoring the denominators we'll get:\[\frac{m+6}{(m-1)(m-2)} + \frac{2m-1}{(m+2)(m-7)}\] now get them to have the same denominators: \[\frac{(m+6)(m+2)(m-7) + (2m-1)(m-1)(m-2)}{(m+2)(m-2)(m-1)(m-7)}\]
hmmm, there's something wrong
are you sure of your question?
LOL! WAIT!
I got the mistake >_< sorry!
it's supposed to be : \[\frac{(m+6)(m+7) + (2m-1)(m-1)}{(m-2)(m-1)(m+7)}\]
so :
\[= \frac{m^2+13m+42+2m^2-3m+1}{(m-1)(m-2)(m+7)}\]\[= \frac{3m^2+10m+43}{(m-1)(m-2)(m+7)}\]
hmm, I'm not sure if we can simplify any further, correct me if I;m wrong please :)
lol, yeah I got the question, but I'm not sure of my answer :)
I am sure of my steps though :)
=) nthank you no your fine im very confuse about this but i trust your answer
thank youuu soooo much!!!
all I did was factor and get them to have the same denominator, and you're welcome ^_^
=) but why did you do those steps
or how? so i can do them for more problems
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