Question

2x^2=5x
solve the equation

Answer 1

2x^2 - 5x = 0

x(2x -5) = 0
x = 0

2x-5 = 0
=> x = 5/2

Answer 2

Okay This can be solve using completing the square technique.
2x^2=5x
2x^2-5x =0
2x^2-5x +( Some number )=0+( Some number )
Right
Now we can find out that (Some number ) by using the (-b/2a)^2
here, our b is -5, a is 2 ( from the form ax^2+bx+c =0)
(-b/2a)^2 = (5/4)^2
2x^2 -5x +( (5/4)^2)= (5/4)^2

Hope you can soleve the LHS now
If you get (x+A)(x+B) =(5/4)^2, u know, (x+A) =(5/4)^2
or (x+B)=(5/4)^2
Now u know how to solve for X. Aske me if it is not clear.