Question

Can someone please explain to me how to find an equation of the line containing the given points (1/6,-1/3) and (5/6,3)

Answer 1

yes :)

Answer 2

1) find out the "slope" between the points by subtracting one from the other

Answer 3

x,y

(5/6 , 3 )
- (1/6, -1/3)
-------------
(4/6,8/3)

slope = y/x = (8/3)/(4/6) and that can be simplified

Answer 4

:D y-y1=m(x1-x)

Answer 5

8/3 8 6
--- = -- * -- = 2*2 = 4
4/6 4 3

slope is = 4

Answer 6

the equation of a line is y = "slope" * x + b; and it needs to contain at least one of the points given :) perferably both; but we have the slope, so we only need one of them to work it out

Answer 7

y = mx + b; (x=5/6, y=3)

3 = (4)(5/6) + b ; solve for b

3 = 20/6 +b

3 - 10/3 = b

-1/3 = b

the equation of the line is:

y = 2x - 1/3 which can be written also as... 2x -y = 1/3

Answer 8

.... arg!! typoed it lol

Answer 9

y = 4x - (1/3)

-4x +y = -1/3

4x -y = 1/3

are all equal equations for this line