Question

Solving for x... Can anybody help? I think I did it right but want to make sure.

Log2 base 2 ^ x-5 = 5

Answer 1

Do you mean\[\log_22^{x-5}\]?

Answer 2

If so, that's\[\log_22^{x-5}=(x-5)\log_22=(x-5).1=x-5\]

Answer 3

Yes that is the equation. Solving for X.

Answer 4

what is X?

Answer 5

Well, you can't solve for x unless \[\log_22^{x-5}=(something)\]

Answer 6

x=10

Answer 7

If there's no '=' sign in your question, it's an 'expression' that you need to simplify.

Answer 8

x=10 does that help?

Answer 9

Sorry - I didn't see the 5

Answer 10

\[x-5=5 \rightarrow x=10\]

Answer 11

Yes It does . Thank you . That is what I got.