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solve the DE using the exact method: y^2dx - x^2dy=0
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how about the solution of the problems u posted earlier?u got it?
p(x,y)=y^2 Q(x,y)=-x^2
yeh got them
these arent exact......they are spearable but it says to solve using exact method
but they can be made exact if we multiply the eq with integarting factor
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again the given eq is not exact :)
yeh but u cant get the integrating factor to be of one variable so that method wont work
yea right
so its impossible to solve using the exact methods
ok lets find the integrating factor
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oh we cant find an integrating factor, darn
so use seperable equations , i get dx/x^2 = dy/y^2
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