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2x-2/x-1
Is that the answer?
yea.
My teacher told me the answer was 2x+8, I was supposed to figure out how to get it
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ok let me see I might have made a careless mistake on min please
ok
Factoring everything I get (((x-4)(x+4))/(5(x-3)))*(10(x-3)²/(x-4)(x-3))
after cancellations u get (x+4)2 => 2x+8
Factor all terms that can be factorized, you get: \[{x^2-16 \over 5x-15}.{10(x-3)^2 \over x^2-7x+12}={(x-4)(x+4) \over 5(x-3)}.{10(x-3)^2 \over (x-4)(x-3)}\] Now, Cancel any common factors, in the numerator and denominator, you get: \[2(x+4)=2x+8\]
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Wow thank you!
darn it.
Thank you
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