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Mathematics 12 Online
OpenStudy (anonymous):

Find the product and simplify your answer completely

OpenStudy (anonymous):

OpenStudy (anonymous):

2x-2/x-1

OpenStudy (anonymous):

Is that the answer?

OpenStudy (anonymous):

yea.

OpenStudy (anonymous):

My teacher told me the answer was 2x+8, I was supposed to figure out how to get it

OpenStudy (anonymous):

ok let me see I might have made a careless mistake on min please

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Factoring everything I get (((x-4)(x+4))/(5(x-3)))*(10(x-3)²/(x-4)(x-3))

OpenStudy (anonymous):

after cancellations u get (x+4)2 => 2x+8

OpenStudy (anonymous):

Factor all terms that can be factorized, you get: \[{x^2-16 \over 5x-15}.{10(x-3)^2 \over x^2-7x+12}={(x-4)(x+4) \over 5(x-3)}.{10(x-3)^2 \over (x-4)(x-3)}\] Now, Cancel any common factors, in the numerator and denominator, you get: \[2(x+4)=2x+8\]

OpenStudy (anonymous):

Wow thank you!

OpenStudy (anonymous):

darn it.

OpenStudy (anonymous):

Thank you

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