Question

4x^2-3x-5=0

Answer 1

Solve for x

Answer 2

\[\left\{x\to \frac{1}{8} \left(3-\sqrt{89}\right)\right\},\left\{x\to \frac{1}{8} \left(3+\sqrt{89}\right)\right\} \]

Answer 3

Can you help me understand

Answer 4

http://www.scientificpages.net/math/images/Quadratic_Formula.gif
you use the quadratic formula!

Answer 5

I bet robtobey used mathematica
use the quadratic formula\[x = (-b \pm \sqrt{b^2-4ac})/(2a) \]
a =4
b = -3
c = -5
plug n play

Answer 6

u could also use the fact that;
\[x1*x2 = -b/a\] and \[x1+x2 = c/a\]

Answer 7

Ok got it thanks

Answer 8

Quick question why does the 8 become 1/8 ?

Answer 9

click on show steps
http://www.wolframalpha.com/input/?i=sovle+4x^2-3x-5%3D0

Answer 10

Thanks