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use the formular nCr to evaluate the expression.8C5/4C3
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\[nCr = nPr/r! => n!/((n-r)!r!)\]
I always go to pascals triangle
8C5 = 8!/(3!5!) = (8*7*3!)/3! = 56 4C3 = 4!/(3!) = 4*3!/3! = 4 8C3/4C3 = 56/4 = 14
And then how do you figure out the whole answer because isn't it suppose to come to one answer all toghether?
because it's only suppose to be one answer because it's a fraction the 8c5 is on top and the 4c3 is on bottom
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1 4 6 4 1 <-- 4C3 = 4 1 5 10 10 5 1 1 6 15 20 15 6 1 1 7 21 35 35 21 7 1 1 8 28 56 70 56 28 8 1 <-- 8C5 = 56 56/4=14 Of course I would only list P's Triangle when I can do it faster than cyter's way
Ok thanks
ur welcome!
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