Question

can someone help with my cal 3? i posted a question and im still stuck.

Answer 1

yeah whats up

Answer 2

ok thanks im going to type it now...

Answer 3

\[\int\limits_{0}^{6}\int\limits_{?}^{?}\]

Answer 4

\[\int\limits_{0}^{5}\int\limits_{0}^{y}(siny/y)\]

Answer 5

dx dy ?

Answer 6

dxdy

Answer 7

with respect to dx, the integral of sin y/y is just a constant so you get [ sin y/y *x ] and you integrate from y to 0

Answer 8

ok so it would be integrate from 5 to 0 (siny^2/2)?

Answer 9

no you didnt plug in y to 0 for x

Answer 10

integral [ sin y/y [ y - 0] dy

Answer 11

when you plug y in for x will the bottom y cancel out?

Answer 12

\[\int\limits_{0}^{y}\]

Answer 13

im lost

Answer 14

its not hard

Answer 15

this latex thing is killing me

Answer 16

what?

Answer 17

it can you please work it out for me?

Answer 18

\[\int\limits_{0}^{5}\int\limits_{y}^{0} siny/y dx dy = \]

Answer 19

forget it, im sick of this , find someone else. this latex is retarded

Answer 20

since siny/y is a constant wouldn't you multiply it times x and then plug y in for x?

Answer 21

yes

Answer 22

go ahead and do that

Answer 23

\[\int\limits_{0}^{5}\]\[\int\limits_{0}^{y}\]

Answer 24

\[\int\limits_{?}^{?}\int\limits_{?}^{?}\]

Answer 25

ok after i did that i got \[\int\limits_{0}^{5}sinydy \]

Answer 26

anyone?

Answer 27

this is baby calculus, cmon