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OpenStudy (anonymous):
hep, hep. okay, i've got my equation to be -1=xsquared+5x I'm solving for x what do i do next?
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myininaya (myininaya):
add 1 to both sides
OpenStudy (anonymous):
alright. then what?
myininaya (myininaya):
x^2+5x+1=0 is it factorable? if not, use the quadratic formula
OpenStudy (anonymous):
............ahhhhh wait i still dont get it.
myininaya (myininaya):
a=1, b=5,c=1 x=[-5@sqrt(5^2-4(1)(1))]/[2(1)] when @ means plus or minus
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myininaya (myininaya):
x=[-5@sqrt(25-4)]/2=[-5@sqrt(21)]/2 x=[-5+sqrt(21)]/2 or x=[-5-sqrt(21)]/2
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