Question

(3x+2)/(x-5)≤ 0

Answer 1

ohhhh, nice pic

Answer 2

wowowowowowo

Answer 3

seriously?

Answer 4

wowowowowowow chick a bow wow

Answer 5

you have two cases

Answer 6

-_-

Answer 7

+ / - and - / +

Answer 8

:)

Answer 9

ok so far?

Answer 10

yupp

Answer 11

those two cases will make it < = 0

Answer 12

so first case + / - , we have (3x + 2) >= 0 and denominator < 0

Answer 13

aren't they both less than 0?

Answer 14

no then you will have negative/ negative wich is positive

Answer 15

gotcha

Answer 16

remember denominator cannot equal zero

Answer 17

thats why x-5 < 0 , not x-5 <= 0

Answer 18

now give me medal,

Answer 19

not until you show me how to do this problem

Answer 20

awwwww

Answer 21

To get cantorset's attention, just have a pretty picture :P

Answer 22

yeah, so he can be an retriceand not focus on the task at hand.

Answer 23

He's trying to get achievements and medals, nothing more.

Do you still need help, alexghe92?

Answer 24

yes please, sorry for the confusion before.

Answer 25

sorry im multitasking

Answer 26

I got a medal for my answer here :D

Answer 27

whoa, why am i an retrice

Answer 28

although I don't deserve it :(

Answer 29

you are a jerk. what makes you so special i have to answer this

Answer 30

what gives you this sense of entitlement. im done here

Answer 31

i gave you plenty of information , yuo just want me to spoon feed this

Answer 32

good luck

Answer 33

retrice

Answer 34

k bye.

Answer 35

I don't think she needs you anymore, since she has Quantum :P

Answer 36

Okay, so right now, you can let it behave as though it's an equation and say that (3x+2)/(x-5)= 0 (for simplicity's sake). Then, multiply both sides by x-5, but on both sides it just disappears, leaving you with 3x+2 = 0. Subtract two, and divide by 3, to get x ≤ -2/3, after replacing the "=" with "≤" (in this case, the direction of the inequality doesn't change, so you don't lose any information by converting between the two. Hope that helped

Answer 37

that wont work quantum

Answer 38

lol

Answer 39

How?

Answer 40

scroll up , there are two cases

Answer 41

+ / - and - / + for when the inequality < = 0

Answer 42

i started the first case

Answer 43

but im just an retrice what do i know

Answer 44

If you're going to type a response, type it in one swoop, don't just break it up into several just to get your achievements.

Answer 45

you have more cases than just x < = -2/3, its a compound inequality

Answer 46

quantum, well im not getting paid

Answer 47

oh god, i just squashed my nads, i was crossing legs

Answer 48

cant breathe

Answer 49

brb, im answering other questions btw

Answer 50

youre right, the second answer is 5.

Answer 51

Alright, I think I made a mistake with my sign change from the l.e. to =. Because you had something in the denominator, it does flip to "greater than or equal to", and thus you have x is greater than or equal to -2/3. And, to have the case that cantorset was talking about, you have to have some region where x-5 < 0, which gives you x < 5. So, we now know that x satisfies the expression anywhere in between -2/3 and 5, including -2/3, and excluding 5.

Answer 52

(It's been such a long time since I worked directly with inequalities! xD )

Answer 53

youve been a bunch of help though, I haven't done these problems since the beginning of the semester and my final exam is on tuesday so I just needed to refresh. Thank you!

Answer 54

Glad to help. :)

Answer 55

so you guys didnt answer this , i will answer it, one sec

Answer 56

-2=3x since (3x+2)/(x-5)\[\le\]0
multiply the (x-5) on each side, on the left side it cancels out, on the right side its 0 (0 times any number is 0.) then remove the parenthesis, subtract two, which gets you 3x=-2. you can simplify this further, which will get you a decimal. (which, im also not going to do.)

Answer 57

Cantorset, it's answered. Definitively.