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i included a picture of the problem. its easier to show you than to type it. really appreciate your help.
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where is it?
right there. thanks QuantumTorch.
Sure thing. Natural log both sides and then it becomes a simple algebraic equation.
I gotta go to bed so I can't be too specific, but you get something like the x-1=(1/4)x+2 or whatever the leftover components were
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I'm sorry, plus the ln of all that
\[e ^{x-1}=(1/e ^{4})^{x+2}\] \[e ^{x-1}=e ^{-4(x+2)}\] and hence \[x-1=-4x-8\] and x=-1.4
thank you for all your help
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