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arcsec(sec pi) - without using tables or calculators
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\[\sec^{-1}(\sec(\pi))\]
cos cot sec are up top..... so it shuold be pi
the domains of cos, cot, and sec are from 0 to pi...the top part of the unit circle; so we just get pi back as the result of your problem
okay, thanks. Is it possible for you to show the steps? I'm being graded for working too..
the steps; hmm..... sec^-1(sec(pi)) sec^-1(-1) = pi I really dont know what "steps" the grader is looking for.
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You me both, lol. Thanks! :)
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