Question

Please! help me check my answe,do even only,
2) Degree
4) GCF
6) Polynomial
8) Simplify
10) Synthetisc dubtitution

Answer 1

http://i1142.photobucket.com/albums/n608/nancylam67/page374.jpg

Answer 2

sorry subtitution not dubtitution

Answer 3

8 = 8
10=4

Answer 4

not solve, just fill the word in the blank

Answer 5

I need check my answer if I correct

Answer 6

8, Simplify
4, synthetic division

Answer 7

seems the choices are too restricted!!

Answer 8

number 10 Synthetisc dubtitution ?

Answer 9

Not for sure, have you googled those words?

Answer 10

no

Answer 11

you have time look another problem?

Answer 12

I don't see any on the list that would match "degree"

Answer 13

I may be of help, what is the probllem?

Answer 14

you want me sent you a lesion degree?

Answer 15

the degree of an equation depends on the highest exponent of the variable, and there was nothing like that on the list.

What is the next problem?

Answer 16

http://i1142.photobucket.com/albums/n608/nancylam67/Page373.jpg

Answer 17

I have looked it over. Here is what I have come up with:

Let x = longer leg
Let y= shorter leg
then 24-(x+y)= hypotenuse
You with me so far. Ask question now about what I have set up for solving this problem.

Answer 18

We are told the following:

3x-2y=24-(x+y)+3 Do you see where that come from?

Answer 19

P: x+y+z=24
The given: (3*x)-(2*y)=h+2
I know from here ,But I don't know next

Answer 20

sorry z for hypotenuse
The given: (3*x)-(2*y)=z+2

Answer 21

O.k I put 3 where it should be 2, my equation should be 3x-2y = 24-x-y +2

Answer 22

then we would have 4x+3y = 26 That is an equation with two unknowns we need to make another equartion. But first need to fix another mistake.
4x-y=26 Do you see why 4x-y=26 cm????

Answer 23

yes I see

Answer 24

This means y=4x-26. Problem says it is a right triangle we know that by pythagorem theorem hypotenuse is equal to the square root of the sum of the legs squared or\[\sqrt{x ^{2}+y ^{2}}\]

Answer 25

we substitute for y and get this:
\[hyp=\sqrt{x ^{2}+(4x-26)^{2}}\]
We also know that the hypotenuse is equal to 24-x-y substituting for y we now have
hypotnuse=24-x-(4x-26)
hyp=-5x+50
\[-5x+50=\sqrt{x ^{2}+(4x-26)^{2}}\]Now we have an equality with one unknown

Answer 26

The radical should extend completely across\[-5x+50=\sqrt{x ^{2}-(16x ^{2}-208x+676}\]

Answer 27

Arte you still there?

Answer 28

From here I just solve for x?

Answer 29

square both sides of the equation
\[25x ^{2}-500x+2500=x ^{2}-16x ^{2}-208x+676\]

This thing keeps getting bigger and bigger!!!\[40x ^{2}-292x+1824=0\]
A quadratic that should be solvable lol

Answer 30

Ok. thank I can do from now

Answer 31

You can divide by 4 and get
\[10x ^{2}-73x+456=0\]

Answer 32

I have one more very quick, can you show me how to write faction on the bottom of the chat, I keep play but I can do it.

Answer 33

I don't know how to write frac on the equation line, if you google latex you will find the math languate they use here.

Answer 34

on the bottom of the chat window

Answer 35

it say Equation

Answer 36

I see every people write fraction

Answer 37

loki showed me how, but I forget, if you look at "latex" it will explain it.

Answer 38

it Ok I will ask pepole around, thank you for spend time solve my problem

Answer 39

I have to go now bye

Answer 40

Ok, somewhere there is an error in the solution as the root is a complex value. I will loolk it over and see where it went wrong.

Answer 41

There were errors, the final quadratic should appear as:\[8x ^{2}-292x+1824=0\]
When solved, you will find x=8 (longer leg)
substitute x in the y=4x-26=32-26=y
y=6 cm (shorter leg)
24-6-8=10cm the hypotenuse
It checks out.