If a car is travelling 80 miles per hour on a slippery road, then its stopping distance D in feet can be calculated by D=(6400/80)*(1/x), where x is teh coefficient of friction between the tires and road and 0

Question

If a car is travelling 80 miles per hour on a slippery road, then its stopping distance D in feet can be calculated by D=(6400/80)*(1/x), where x is teh coefficient of friction between the tires and road and 0<x< or equal to 1.
multiply and simplify the formula for D
and 
Compare the stopping distance on an icy road with x=0.2 and on dry pavement with x=0.8.

so
D=?
the stopping distance on an icy road is ?? feet.(round to the nearest whole number as needed)
the stopping distance on dry pavement is?? ft.

When a car is moving at 80 miles per hour, the stopping distance on dry pavement is__ of

dumbcow · Answer

D = 80/x  you are just reducing
x=.2 -> D = 80*5=400
x=.8  -> D=80*(5/4) = 100

anonymous · Answer

what about if teh car is moving at 80 miles per hour the stopping distance on dry pavement is __ of the stopping distance of an icy road?? (type as an integer or simplified fraction)

anonymous · Answer

I really appreciate your help

dumbcow · Answer

i already answered that....we are already assuming car is going 80 mph its already factored into equation for D