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Mathematics 11 Online
OpenStudy (anonymous):

a family has 5 children. the probability of having a girl is 1/2. what is the probability of having no girls?

OpenStudy (anonymous):

suppose you have a coin. what is the probability of it landing heads?

OpenStudy (anonymous):

ok i know the answer to the question is .0313, anyone know how?

OpenStudy (anonymous):

see if 1/32 is 0.0313

OpenStudy (anonymous):

yeah how did you get 32

OpenStudy (anonymous):

the probability of having a girl is 1/2. so the probability of having a boy is 1/2. in a family of 5 children, all are boys. i.e, there are no girls. so the parents had five boys consecutively. so the probability of having 5 boys in a row is 1/2 times 1/2 times 1/2 times 1/2 times 1/2

OpenStudy (anonymous):

ok thanks, know how to get this one? a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. find the probability you with pick 2 cherry and 1 lemon

OpenStudy (anonymous):

yes, but do you want the answer or do you want to learn how to do this?

OpenStudy (anonymous):

learn how, i know the answer

OpenStudy (anonymous):

okay. so suppose you have 2 candies in the bag. one is lemon and one is grape. what is the probability that you will pick the lemon candy?

OpenStudy (anonymous):

1/2

OpenStudy (anonymous):

okay good. suppose you have three candies. one lemon one grape and one cherry. what is the probability you pick the lemon ?

OpenStudy (anonymous):

1/3

OpenStudy (anonymous):

okay good. suppose you have three candies, two lemon and one cherry. what is the probability you pick a lemon candy?

OpenStudy (anonymous):

2/3

OpenStudy (anonymous):

okay very good. now you have 6 cherry, 3 lemon and 2 grape candies. what is the probability that you pick one cherry candy?

OpenStudy (anonymous):

6/11

OpenStudy (anonymous):

okay very good. now, you have already picked one candy. so there are ten candies left. 5 cherry, 3 lemon and 2 grape. what is the probability that you pick a cherry candy?

OpenStudy (anonymous):

5/10 so 1/2

OpenStudy (anonymous):

yes, good. now there are 9 candies left. 4 cherry, 3 lemon and 2 grape. what is the probability that you pick a lemon candy?

OpenStudy (anonymous):

3/9, and then you multiply right? thats how i tried to solve the original one but i got the wrong answer

OpenStudy (anonymous):

yes, so the probability that you pick 2 cherry candies in a row and then one lemon candy is 6/11 times 1/2 times 1/3.

OpenStudy (anonymous):

for 6 cherry, 3 orange, and 2 lemon; the prob of 2 cherry and 1 lemon: answer is supposed to be .1818

OpenStudy (anonymous):

solving its that way gets .0909

OpenStudy (anonymous):

the question says there are only 2 lemon candies and there are 3 orange candies. so for the third try, you pick a lemon candy out of 9 candies, the probability of that is 2/9 so the answer should be 6/11 times 1/2 times 2/9

OpenStudy (anonymous):

yeah i can do that and get .0606; but the book says the answer is supposed to be .1818

OpenStudy (anonymous):

thats why im confused

OpenStudy (anonymous):

wait, is that supposed to be in that order?

OpenStudy (anonymous):

it says at random

OpenStudy (anonymous):

yeah it says random, but is the expected answer 1 cherry then 1 cherry then 1 lemon or is it that you pick three candies and you end up with 2 cherries and 1 lemon?

OpenStudy (anonymous):

okay looks like you are not reaching in three times. you just reach in once and take three candies.

OpenStudy (anonymous):

it says "you reach in and take 3 pieces of candy at random"

OpenStudy (anonymous):

do you know how to figure it out that way?

OpenStudy (anonymous):

yeah. you have to do it the following way: 6C2/11C3 times 2C1/11C3

OpenStudy (anonymous):

c?

OpenStudy (anonymous):

have you done permutations and combinations? BTW ignore my answer. that is incorrect. I will calculate the correct answer and post it here.

OpenStudy (anonymous):

my teacher gave us problems to do but never taught us how, but yes we are supposed to be doing permutations and combinations. any quick formulas i can jot down for the test?

OpenStudy (anonymous):

The answer is 6C2 times 2C1 divided by 11C3

OpenStudy (anonymous):

ohh ok that makes sense! thanks!

OpenStudy (anonymous):

so that is 15 times 2 divided by 165 = 30/165 = 0.181818181

OpenStudy (anonymous):

you dont know how to do combinations?

OpenStudy (anonymous):

nope:(

OpenStudy (anonymous):

then how did it make sense to you?

OpenStudy (anonymous):

she showed us the calculator commands for the c but didnt show us what it was for, now i know

OpenStudy (anonymous):

read through that and ask me if you have doubts.

OpenStudy (anonymous):

thanks soo much!

OpenStudy (anonymous):

probability in poker, a flush in any suit?

OpenStudy (anonymous):

what is your question?

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