Question

Convert the equation to polar form.

x^2-y^2=7

Answer 1

x=rcos(theta)
y=rsin(theta)
(rcostheta)^2-(rsintheta)^2=7

Answer 2

what is r and theta, that's what confuses me

Answer 3

do you not see what I scanned for you?

Answer 4

i did

Answer 5

i put a point on (x,y) and theta is the angle between the initial ray and the vector with endpoint (0,0) and (x,y) ( r is like the length of this vector except it can be negative)
r is like the radius of a circle sortof except it can be negative
r is the directed distance from the origin
so if is negative you go the opposite a way
anyways
i drew a triangle, a right trinagle
and i found cos(theta)=x/r
and sin(theta)=y/r
so that means
rcos(theta)=x
and
rsin(theta)=y

Answer 6

so (x,y)=(rcos(theta),rsin(theta))

Answer 7

i understand that but i have no idea when it comes to plugging in the numbers