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OpenStudy (anonymous):
What is the formula for solving a triangle with the law of cosines if you have all the side lengths but need to find the angles?
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OpenStudy (amistre64):
c^2 - a^2 - b^2 -------------- = cosC 2ab
OpenStudy (amistre64):
its the law of cosines solved for cosC
OpenStudy (amistre64):
to get the angle youll need to take the consine inverse tho... and keep in mind that cos^-1 spits an angle out in the range of 0 to pi...so adjust as needed
OpenStudy (amistre64):
hah... i see a typo
OpenStudy (amistre64):
/-2ab... | c^2 - a^2 - b^2 | cos^-1 |--------------- | = C ; adjusted of course | -2ab |
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