Question

Can someone help me solve, 4sin^2(theta)=3+cos^2(theta),
for values of theta between 0 and 360 degrees.
thank you :)

Answer 1

sin^2 (t) +cos^2(t) = 1 (by definition)
so, cos^2(t) = 1-sin^2(t)
substitute:
4sin^2(t) =3+1-sin^2(t)
add sin^2(t) to both sides:
5sin^2(t)=4
divide by 5 both sides:
sin^2(t) = 4/5
sin(t)= 2/sq.rt(5)

Answer 2

thanks :)