Question

use the properties of limits to fin the indicated limit: lim x->5- x^2+25/x+5

Answer 1

as x goes to 5 from the left, there is no division by zero, so why not substitute?

Answer 2

Is it really x^2+25/x^2+5?

Answer 3

yes

Answer 4

with lim of x->5-

Answer 5

I still don't see the issue, unless it is really the limit as x goes to negative 5 of (x^2 + 25)/(x + 5) otherwise, you can substitute directly. If it is this, though...

Answer 6

ooh ok thank you

Answer 7

The only problem with simply plugging the value of x in would be is if that would cause the denominator to go to zero.

Answer 8

Oh ok :)