Question

125x^4 y^-5
(------------) ^2
5x^6 y^-5

Answer 1

You need to take the (126x^4y^-5)^2 first.

Answer 2

Sorry 125

Answer 3

first line is y^-3 sorry...not -5

Answer 4

Is the problem
(125x^4y-3)^2
------------
5x^6y^-5

Answer 5

yes :)

Answer 6

OK.. order of operations says to ^2 first so

(125x^4y^-3)^2 is 125*125 = 15625 x^8y^-6 (multiply exponents when you take a power to a power)

Answer 7

15625x^8y^-6
-------------
5x^6y^-5

Answer 8

ok I follow

Answer 9

3125x^2y^-1 you divide 15626/5 = 3125 you subtract exponents
x^(8-6) x^2 and
y^(-6 - -5) y^-1

Answer 10

You can't have a negative exponent so you put the y term on the bottom to the positive power

3125x^2
--------
y

Answer 11

k, so this is the answer? Thanks for your help!!!

Answer 12

yes

Answer 13

can u help me with one more....

Answer 14

y^-6 Z^0
--------
y^-3

Answer 15

y^-6 z^0
--------
y^-3 first of all anything to the 0 power is equal to 1

y^-6 (1)
----
y^-3

y^-6
----
y^-3 you subtract exponents ... be careful... it is top minus bottom.

so y^(-6 - -3) so y^(-6 + 3) so y^-3

but because we can't have a negative exponent. it is

1
--
y^3

Answer 16

Great!! I get it. Thanks a million!

Answer 17

No problem.