how do i find the slope intercept form of 3x-2y=-16?
solve for y
3x-2y = -16 ; -3x -2y = -3x - 16 ; /-2 y = -3x/-2 -16/-2 y = (3/2)x +8
what is the -3x for?
is y=(3/2)x+8 the answer?
when we have an equal sign in there that means that both saides are balanced; they weigh the same
we have to keep them balanced so whatever we do to one side we have to do to the other....right
how do we get y all by its little lonesome? first we have to -3x from it right?
can you walk me through the rest of the problem?
3x-3x -2y = -16-3x 0 -2y = -3x-16 -2y = -3x-16 do you agree?
yes
now we have a -2 stuck the the 'y'...and its stuck there by multiplication....we remove it by dividing. (-2/-2)y = (-3x/-2) -(16/-2) 1y = (3/2)x + 8 y = (3/2)x+8 ; do you agree?
by doing albegraic techniques we simply change the way the problem looks; not the value of it...jus tthe shape of it
yes! so y equals (3/2)x+8?
unless you came to another conclsion without me...then yes, the final answer is the final answer :)
thank you!
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