Question

Having trouble with another boundary condition question:
y"+4y'+13y=0
Boundary condition:
y'(0) = 0 and y'(pi) = 1
I get the general solution:
y = e^(-2x) (Acos3x + Bsin3x)
I think I may be doing this one wrong cause the last boundary condition doesn't work???

Answer 1

did you find the Lagrange multiplier?

Answer 2

Erm no?

Answer 3

i will scan something and see if it helps you k? just a sec

Answer 4

Thanks again...

Answer 5

do you see the two equations i got to solve for the constants

Answer 6

is that what you got?

Answer 7

i will try to do it after i finish eating

Answer 8

Yeh I got that, it's the y'(pi) bit i dont get, cheers enjoy your food...

Answer 9

I couldn't find the constants with those boundary conditions

Answer 10

any luck yuki?

Answer 11

So what would the solution look like?

Answer 12

i think the solution that satisfies both boundary conditions and the different equation is
y=0 but wait 1 does not equal 0
so let me think about this some more
it can't simply be there is no solution or can it...

Answer 13

I'm not sure, not come across a question where the boundary condition fails??

Answer 14

me either

Answer 15

Hmmm, I may have to investigate further, don't really know enough about these types of questions yet??

Answer 16

no solution
it is possible

Answer 17

Do you think I should leave it as no solution then??

Answer 18

http://tutorial.math.lamar.edu/Classes/DE/BoundaryValueProblem.aspx
it happened here

Answer 19

I'll check :-)

Answer 20

yes
i would say no solution
but show your work leading to that conclusion

Answer 21

i would say there is based on the boundary conditions there is no solution

Answer 22

Excellent, you've been ace, thanks...

Answer 23

thanks
:)