Question

@Yuki (or whoever gets to it first) so would you use the same techniques you were showing me for this one? it is in an attachment >.< sowee im confused... :P

Answer 1

the first one is the equation your simplifying the next 3 are the options :)

Answer 2

Eh, I would just factorise the first term, then multiply by the inverse of \[n+4 / n-3\]

Answer 3

So the first term reduces to (n+4)^2/(n-3)^2 after factorising then you just multiply that by (n-3)/(n+4) which cancels the first to (n+4)/(n-3)

Answer 4

Ahhh i see i would have gone with C i wish there were a quicker easier way to find the answers to these things that werent so dang complicated!! :P lol but thanks a bunch just helped me slot!! :D

Answer 5

your welcome :D

Answer 6

so then the answer to this one would be : wait here i will attach them can u do the last two with me? pls? :)

Answer 7

OK

Answer 8

option C = 1

Answer 9

OK so factorise (n^2 + 3n + 2) to (n+2)(n+1), so it becomes \[((n+2)(n+1))\div2\] then multiply that by the reciprocal of (n+1)/(2(n+2)) which is 2(n+2) / (n+1) , both the 2s cancel and the (n+1)s cancel so its just (n+2)^2

Answer 10

Ahhhh alright i see the "pattern" or whatever lol okie dokie last one and its on long division UGH :P i stil cant get the hang of it :P

Answer 11

Option A = x + 5
Option D = x - 7

Answer 12

OK well can you do long division? Kinda hard to show it on here but I can try

Answer 13

:P i hate long division URGHHHH

Answer 14

ok so do you think you could attach the steps?

Answer 15

Lol
x - 9
______________
x+7/x^2 - 2x - 30
x^2 + 7x
--------
-9x - 30
-9x - 63
----------
33 <- remainder

so it's
x - 9 + 33/(x+7)

Answer 16

Ok im pretty sure i get it now, well more than i got it before :) lol thanks :)

Answer 17

http://www.youtube.com/watch?v=3ULXhiJqlPs&feature=relmfu

http://www.youtube.com/watch?v=l6_ghhd7kwQ&feature=channel_video_title

Answer 18

i always get so wrapped up in the solving underneath the division thing i forget about above it ^^

Answer 19

haha!! thx!! :)

Answer 20

Yeah.. I remember doing long division of polynomials last term, it's annoying cause I never used to use long division in lower school I just did the divisions in my head so I had no idea how to do long division. Good luck and you're welcome..

Answer 21

yea ikr lol thx :)