Question

OR || UE || NT
f =?, g = ?

Answer 1

what is this?

Answer 2

lol..isnt it a simple....?

Answer 3

i just need help with my homework

Answer 4

\[\frac{f}{36}=\frac{32}{48},f=24\text{ };\text{ }\frac{g}{32}=\frac{30}{24},g=40 \]

Answer 5

can u help me with the another question

Answer 6

go ahead

Answer 7

What is the second problem?

Answer 8

Yes, type in your other question.

Answer 9

TA || UR
Is QTA about to TUR?
Is QAT about to ARU?
Why is QTA ~ QUR?
e =

Answer 10

Hold on....

Answer 11

These appear to be proportional problems.
This one says,
The quantity 3+T is to 5 as 4+A is to e. The is from the geometry the triangle in your jpg.
"is to" is replaced by divide and "is to" is replaced by e.\[\frac{3+T}{5}\text{=}\frac{4+A}{e},\text{ }e=\frac{5 (4+A)}{3+T}\]
e come from solving the equation on the left for e.

Does this help you?

Answer 12

not really

Answer 13

There is some incorrect english in this answer.
First the math is correct as far as I can see.

From the geometry in your triangle diagram, you have a line passing through the triangle. The line appears to be parallel to the base line of the triangle. From plane geometry, and it's been along time since I studied plan geometry, the line segments on the sides formed by the line passing through them are proportional to each other as shown in the equation.

e was solved for in terms of A and T. There is not enough given dimension information to solve in terms of real numbers.

Answer 14

Is e the number 2.7...?

Answer 15

so what should i do?

Answer 16

Is e the transcendental number 2.718 ?

Answer 17

how u do u get thast

Answer 18

e is a very important mathematical constant.

http://en.wikipedia.org/wiki/E_%28mathematical_constant%29

From your reaction I guess that your e is not the mathematical constant e.

Answer 19

There were enough numbers provided in your first problem to obtain numerical values for all the line segment lengths.

In the second problem there are three unknowns and not enough numerical information to solve for these unknowns.

I guess that I have given you the best answer to this problem that I can

Have to leave now.