graph l x-3l = y what steps do i do to find out what points to plot
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OpenStudy (amistre64):
x=|y=
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OpenStudy (amistre64):
make a table of points...
OpenStudy (anonymous):
|x-3|=y means that two equations are there
1) x-3=y
2)x-3=-y;
then solve as you find points
in equation 1 & 2 put some points of x and evaluate corresponding y
OpenStudy (amistre64):
when x=0; y=3
when x=-1; y=4
when 3=1; y=2...etc
OpenStudy (amistre64):
x=1...not 3=1 lol
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OpenStudy (anonymous):
say x=0 gives you -3 for equ 1 and 3 for equation 2. and so on
OpenStudy (amistre64):
splitting it up complicates matters; makes you want to form an x
OpenStudy (anonymous):
haha a typo isnt as bad as feeling stupid for not being able to figure out something such as this. I am just fried. Learning a month of algebra in one week
OpenStudy (amistre64):
when x=5; y=2 and y=-2? nah....
when x=5; y=2
OpenStudy (amistre64):
in fact y is never gonna be a negative number
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OpenStudy (anonymous):
i give a plot of the graph...
OpenStudy (anonymous):
Thanks For the help guys. i appreciate it!
OpenStudy (amistre64):
that aint it lol.... its y=|x| shifted to the right by 3
OpenStudy (amistre64):
that one you drew up is y=|x|-3
OpenStudy (amistre64):
just plug in numbers for x and tabulate the y from there; plain and simple