Question

6b^2-5b=4
solve the equation and check your solution

Answer 1

To solve it, you must get everything to one side so the equation equals zero.

6b^2 - 5b - 4 = 0

Then factor it.

Answer 2

Do you know how to factor that?

Answer 3

no thats as far as ive gotten

Answer 4

is the 6b^2-5b-4=0

Answer 5

Do you know if you use trial and error, bottoms up, or what method you usually use?

Answer 6

foil

Answer 7

Foil would be to check it

Answer 8

Factoring is taking it apart. We'll use trial and error.
Multiply the first and last numbers and you get -24

Answer 9

What multiplies to be -24 and adds to be -5 (the middle term)

Answer 10

3 and 8

Answer 11

Yeah, 3 and -8. So you know your "inner" and outter terms have to equal 3 and

Answer 12

6 factors to be 2 * 3 or 1 * 6 and 4 can be 2 * 2 or 4 *1

Answer 13

You know you have to have "3" for one of your numbers, so you know it's set up like this....
(3x + ____) (2x + ____)

Answer 14

Since you know you need a 3. that last blank must be a positive 1. (3x + ___)(2x + 1) . That makes your outter terms equal 3.

Answer 15

Therefore your inner terms must equal -8. So what would need to go in that blank?

Answer 16

-4

Answer 17

Yup. So that gives you
(3x - 4)(2x + 1) Then to check it, just FOIL it back together.

Answer 18

ok thanks

Answer 19

you're welcome

Answer 20

wait shouldnt the answer come out to be x= and then like 2 fractions cause on the last one that i did that asked for the equation to be solved and check solution it came out to be n=-1/3 and 2/5

Answer 21

Yes, just set each ( ) equal to zero and solve. The answers should be x = 4/3 and x = -1/2