12x^2-1=-x
solve the equationa dn check your solution

Question

anonymous · Answer

first put it in the standard form ax^2+bx+c =0
and post it here

anonymous · Answer

??

anonymous · Answer

add x to both sides of the equation and post what you get.

anonymous · Answer

i dont get what you mean so yeahhh

anonymous · Answer

have you done algebra before?

anonymous · Answer

no

anonymous · Answer

lol then how come you have to do these questions?

anonymous · Answer

oh. okay. Then you really shouldn't be doing this sort of problem. Let me post a couple of links so that you can first learn some basic algebra and then come back here.

anonymous · Answer

this is my first year doing algebra and i have a 27% and have to retake it next yuear

anonymous · Answer

http://www.youtube.com/watch?v=-voEH-F8qNI http://www.intmath.com/basic-algebra/basic-algebra-intro.php http://www.youtube.com/watch?v=CsmZHxK-Fg4&feature=related

anonymous · Answer

oh. You really should learn how to do these questions. They're not hard ^^ Here's your answer with explanations:

12x² - 1 = -x

[[move everything to one side and get the equation into the general form ax²+bx+c =0]]

12x² + x - 1 = 0

[[You're looking for 2 numbers, m and n, with the conditions that m+n = b and mn = ac. So in this case, two numbers that add to be 1 and multiply to be -12. 4 and -3 work, so split x into 4x and -3x]]

12x² + 4x - 3x - 1 = 0

[[Factorize by grouping in pairs]]

4x(3x + 1) - (3x + 1) = 0

[[Factorise (3x+1) out]]

(4x - 1)(3x + 1) = 0

[[Solve]]

x = 1/4 or x = -1/3