Does anybody know how to solve rational equations with polynomial denominators?

Question

anonymous · Answer

if so comment and i will post the question ^^

yuki · Answer

I do

yuki · Answer

I helped someone with that so I will guid you there

anonymous · Answer

Alrighty thx!! :) the problem is:

   x     =    1    +1
2x+4      x+2

anonymous · Answer

i dont know how to do the lines underneath ^^

yuki · Answer

it's in clark's problem the idea is there, so if you want to know the steps they are all there

anonymous · Answer

Alrighty!!! can u link me maybe?

anonymous · Answer

http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dc4893ba5918b0b16d88120

yuki · Answer

actually, yours is an equation. not an inequality, so nvm

yuki · Answer

uh... I just noticed this but what did I do ? lol
there are so many postings... creepy

anonymous · Answer

Wow!! that looks like exactely what i need!!! :D thanks a bunch!!! :) Totally giving u medals lol :)

yuki · Answer

wait up 1<3, yours is different and much easier so stay here and listen

anonymous · Answer

alright im listening!! :)

yuki · Answer

$${x \over 2x +4 } = {1 \over x+2 } +1 $$

yuki · Answer

right ?

anonymous · Answer

You can also watch Sal on khanacademy: http://www.khanacademy.org/v/solving-rational-equations-1?p=Algebra%20I%20Worked%20Examples

anonymous · Answer

Alright u guys have helped me massively!! :) Now i gtg and do more work :P might not be on later depends on if i need help or not or if i have time ^_^ lol

yuki · Answer

the first thing you want to do here is to find out the common denominator for all terms you have,

anonymous · Answer

gl!

anonymous · Answer

Thanks :)

yuki · Answer

I'll leave the steps so that you can look at it later ok ?

anonymous · Answer

Ahww thank you that is extremely helpful of u =3

anonymous · Answer

cuz i k i will definitely look at the steps ^_^

yuki · Answer

the LCD is 2x+4, so if you multiply that on both sides you will get

$$x = 2 + 2x+4$$

yuki · Answer

if you solve that 

x = -6

yuki · Answer

the only thing you have to be careful is to make sure that when you start the problem, you identify the "extraneous solutions'

basically the x's that makes any denominator in our eqn =0

since x = -2 is such number, it will never be the answer

yuki · Answer

since we did not deduce that x = -2, we just ignore it,

but if x =-2 was what we deduced, then there is no solution.

okay, hope you do well.

anonymous · Answer

Thanks a BUNCH!!!! ur steps totally helped me :)