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Mathematics 21 Online
OpenStudy (anonymous):

5x^2-7x=0

OpenStudy (anonymous):

we need help badly :/

OpenStudy (anonymous):

x=7/5 , 0

OpenStudy (anonymous):

how did you get that answer?

OpenStudy (amistre64):

we?? need help?

OpenStudy (anonymous):

factor out x to get x(5x-7)=0 this means that either x=0 or 5x-7 =0

OpenStudy (amistre64):

factor the equation (x)(5x-7) = 0 we know that anything times 0 = 0 right?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

0(5x-7) = 0 (x)(0) = 0 2 options

OpenStudy (amistre64):

makes sense?

OpenStudy (amistre64):

yall must be typing on Internet explorer :)

OpenStudy (anonymous):

a little were confused cause of the squared

OpenStudy (anonymous):

5x^2-7x=0 you factor out x. So you get: x(5x-7)=0. Then you have two solutions which are: x=0 and 5x-7=0 you have x=0 solve. now you have to solve the second part which is 5x-7=0, which we get 5x=7..then we divide by 5 to 7 which we end up getting x=7/5. so your answers are x=0 and x=7/5

OpenStudy (anonymous):

yeah we are but we are trying to do the answer

OpenStudy (amistre64):

i had to switch to firefox; less buggy in this site

OpenStudy (anonymous):

chrome is best for this site IMO

OpenStudy (anonymous):

yayay! thank you! we got the right answer then

OpenStudy (amistre64):

yay!!! :)

OpenStudy (anonymous):

yay! I share your joy

OpenStudy (anonymous):

lol

OpenStudy (amistre64):

i tell my kids when they get math wrong. i say, quit breaking the math...when its gone thats it :)

OpenStudy (anonymous):

we dont have anyone in out house hold that knows math

OpenStudy (anonymous):

am a math major am about to graduate already from college if any help with with basic proof and from calculus four to and down ill be happy to help.

OpenStudy (amistre64):

still using an abacus eh :)

OpenStudy (anonymous):

can you help us on the next one?

OpenStudy (amistre64):

there more?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

ok......but they better be easy ;)

OpenStudy (amistre64):

gotta let my sister use her facebook ...... ciao :)

OpenStudy (anonymous):

5x^2-8x+3=0

OpenStudy (amistre64):

x- /5 ; x- /5 5(3) = 15 1,15; 3,5 = 8 x- 3/5 ; x- 5/5 5x-3 ; x-1 x = 1 and x = 3/5

OpenStudy (amistre64):

georgia math lol

OpenStudy (amistre64):

sister got distracted by a butterfly ...hurry up

OpenStudy (anonymous):

i dont get it

OpenStudy (amistre64):

dont get what?

OpenStudy (anonymous):

5x^2-8x+3=0 first we have to factor the whole problem which we get (5x-3)(x-1)=0, then we have again two solutions which are 5x-3=0 and x-1=0 now lets solve 5x-3=0. which we get 5x=3 and then divive 5 to 3 which we get x=3/5 now we solve for x-1=0. we get x=1. we are done so out two solutions are x=3/5 and x=1

OpenStudy (amistre64):

my method or the answer?

OpenStudy (anonymous):

your method

OpenStudy (amistre64):

lol..... if it can factor into integers; my method will get to it everytime :)

OpenStudy (anonymous):

LOL THEIR SWARMING THE PRETTY GIRL XD

OpenStudy (amistre64):

i use the clues that are given in the equation to narrow my options

OpenStudy (anonymous):

3y^2+5y=2

OpenStudy (amistre64):

ihave an option; either divide that 5 out to begin with or do it in the end; i choose to wait til the end

OpenStudy (anonymous):

newton yuou explain better then my teacher

OpenStudy (amistre64):

3y^2 +5y -2 = 0 split it up into its form..... set it up y y the last number has a sign that tells yuou to add or subtract... -2 means subtract gonna be a + and a - y+ y- gonna need to divide that three but do it at the end... y+ /3 ; y- /3

OpenStudy (amistre64):

multiply 1st and last number to get option for the middle 3(2) = 6....factor the 6 1,6 well, 6-1=5 so thats what are middle number needs to be y+6/3 ; y-1/3 reduce

OpenStudy (amistre64):

y+2 ; y-1/3 we can stop here to get the zeros or continue to the final form...if theres a fraction left over, stick the bottom of it in front like this: y+2 ; 3y-1 y = -2; y= 1/3

OpenStudy (amistre64):

if it dont factor like this; you should either complete the square method; or quadratic formula ..

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